Rearrange a given linked list in-place
You're given a singly linked list L0 → L1 → ... → Ln. Reorder it in place by alternating from the two ends inward: L0 → Ln → L1 → Ln-1 → L2 → Ln-2 ...
Input Format
Implement rearrange(head). Inputs below show JavaScript function arguments; there is no stdin parsing.
Linked lists use value arrays. The editor passes nodes with val and next properties; [] becomes null.
Output Format
Modify argument 1 in place. The editor compares its final value; the function return value is ignored.
Returned list heads are displayed as value arrays; a null head is [].
Sample Input and Output
Example 1 · Run Sample
Input
head = [1,2,3,4,5] Output
[1,5,2,4,3] Example 2
Input
head = [1] Output
[1] Constraints
- 1 to 5 * 10^4 nodes
- 1 <= Node.val <= 1000
Test Cases (2)
Case 1
Args: [[1,2,3,4,5]]
Expected: [1,5,2,4,3]
Case 2
Args: [[1]]
Expected: [1]
Topics
Find Mid + Reverse + Interleave
function rearrange(head) {
let slow = head, fast = head;
while (fast.next && fast.next.next) { slow = slow.next; fast = fast.next.next; }
let second = slow.next; slow.next = null;
let prev = null;
while (second) { const next = second.next; second.next = prev; prev = second; second = next; }
let first = head; second = prev;
while (second) { const n1 = first.next, n2 = second.next; first.next = second; second.next = n1; first = n1; second = n2; }
}Time: O(n) | Space: O(1)
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